

ANSWER
Question 1(a) was reportedly popular among the candidates and many candidates performed well. However, quite a number of them displayed poor knowledge of ratio by substituting the values 2 and 3 for x and y respectively. They were expected to recognise that if x:y = 2:3 then x/y = 2/3 or x = 2y/3. Similarly, they can be expressed as x = 2k and y = 3k where k is a constant.
Question 1 (b) was also well attempted. However, it was noticed that many candidates could not draw the diagram. Others did not add the man’s height to the calculated height and hence lost some marks.
Question 2 

(a) Simplify: x^{2} – 8x + 16 . (b) If ½, 1/x, 1/3 are successive terms of an arithmetic progression 
ANSWER
The question on Arithmetic progression was not well handled by the candidates. They were unable to recall that since ½, 1/x, 1/3 were terms of an A.P., hence 1/x – ½ = 1/3 – 1/x.
Thus 2 – x = x – 3
2x 3x
which by cross multiplying and simplifying leads to 2 – x = 2x/3x
3 – x
= 2/3 as required.
question 3 

A bucket is 12cm in diameter at the bottom, 20cm in diameter at the open end and 16cm deep. If the bucket is filled with water and emptied into a cylindrical tin of diameter 28cm, calculate the depth of water in the tin. 
ANSWER
Majority of the candidates found this question rather challenging because they could not manipulate the concept of similar figures to find h, the height of the removed cone i.e.
h = 16 + h
6 10 which gives h = 24cm.
Very few of them were able to apply the formular for finding the volume of a frustum V = 1/3 π/ h (R2 + Rr + r2), where V = volume of a frustum.
question 4 

(a) solve the equation: 2logx – log(1 – x) = log(2 – x). 
ANSWER
Many candidates attempted the (a) part of the question and the performance was fair. However, in expressing the logarithm, some candidates wrongly wrote
log x^{2} = log (2 – x) instead of log x^{2} = log (2x)
log(1x) 1x
The part (b) of the question was poorly done. Their apparent difficulty was in reducing the word problem to simple equations. Candidates were expected to assign variables say x and y to represent the amount of money Ade and Chidi have respectively. The required equations are: x – 5 = y + 5 (or x – y = 10) and
x + 5 = 2(y – 5) i.e. 2y – x = 15. On solving simultaneously, x = N35 and
y = N25.
question 5 

(a) A rectangular field is I metres long and b metres wide. Its perimeter Is 280 metres. If the length is two and a half times its breadth, find the values of I and b. , 
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question 6 

(a) If 2x+y = 16 and 4x+y = 1/32, find the values of x and y. 
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question 7 

(a) Solve, correct to two decimal places, the equation 4x^{2} = l1x + 2l. 
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question 8  

(a)Form a frequency distribution of the data using the intervals: 21 – 25, 26 – 30, 31 – 35, etc. (b)Draw the histogram of the distribution. (c)Use your histogram to estimate the mode. (d)Calculate the mean age 
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question 9 

(a) The triangle ABC has sides AB = 17m, BC = 12m and AC = 10m. Calculate the ; (i) Largest angle of the triangle; (ii) Area of the triangle. (b) From a point T on a horizontal ground, the angle of elevation of the top R of a tower RS, 38 m high, is 63°. Calculate, correct to the nearest metre, the distance between T and S . 
ANSWER
question 10 

Using ruler and a pair of compasses only, construct: 
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question 12 

(a) Copy and complete the table of values for y = 3 sinx + 2 cos x for 0 degrees </ x</ 360 degrees
(d) Find the range of values of x for which 3sin x + 2 cos x < – 1

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question 13 

(a) If 3,x,y, 18 are in Arithmetic progresion (A. P), find the values of x and y. (b) (i) The sum of the second and third terms of a geometric progressio,n is six times the fourth term. Find the two possible values of the common ratio. 
ANSWER